F(n)=n^2/5n

Solution for F(n)=n^2/5n equation:

(F)=F^2/5F

We move all terms to the left:

(F)-(F^2/5F)=0


Domain of the equation: 5F)!=0

F!=0/1

F!=0

F∈R


We get rid of parentheses

-F^2/5F+F=0

We multiply all the terms by the denominator


-F^2+F*5F=0

We add all the numbers together, and all the variables

-1F^2+F*5F=0

Wy multiply elements

-1F^2+5F^2=0

We add all the numbers together, and all the variables

4F^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$F=\frac{-b}{2a}=\frac{0}{8}=0$